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Tipologia: Exercícios
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192.168.10.
10.250.1.
172.31.15.
192.168.10.
192.168.10.
Workbook
Variable-Length Subnet Mask
Version 1.
IP Address Classes Class A 1 – 127 (Network 127 is reserved for loopback and internal testing)Leading bit pattern 0 00000000.00000000.00000000.
Class B 128 – 191 Leading bit pattern 10 10000000.00000000.00000000. Class C 192 – 223 Leading bit pattern 110 11000000.00000000.00000000. Class D 224 – 239 (Reserved for multicast) Class E 240 – 255 (Reserved for experimental, used for research)
Private Address Space Class A 10.0.0.0 to 10.255.255. Class B 172.16.0.0 to 172.31.255. Class C 192.168.0.0 to 192.168.255.
Default Subnet Masks Class A 255.0.0. Class B 255.255.0. Class C 255.255.255.
Network. Host. Host. Host Network. Network. Host. Host Network. Network. Network. Host
This workbook assumes you already have a background in subnetting. If you don’t you may want to consider completing the IP Addressing and Subnetting Workbook.
0
127 255
128
0
127 255
128
63 64 192
191
0
127 255
128
63 64 192
191
32
31
95
96
159
223
224
160
/ 255.255.255. 128 Hosts 2 Subnets
/ 255.255.255. 64 Hosts 4 Subnets
/ 255.255.255. 32 Hosts 8 Subnets
Split the box in half and you get two subnets with 128 addresses,
Divide the box into quarters and you get four subnets with 64 addresses,
Split each individual square and you get eight subnets with 32 addresses,
0
127 255
128
63 64 192
191
32
31
95
96
159
223
224
160 15 16 48
47
79 111 80 112
143 175 144 176
208 240
207 239
/ 255.255.255. 4 Hosts 64 Subnets
/ 255.255.255. 8 Hosts 32 Subnets
/ 255.255.255. 16 Hosts 16 Subnets
Split the boxes in half again and you get sixteen subnets with sixteen addresses,
The next split gives you thirty two subnets with eight addresses,
The last split gives sixty four subnets with four addresses each, You can use these squares in any combination to fit your addressing needs.
VLSM Addressing (Sample) Problem 2 Using the network diagram and information given create an addressing scheme which utilizes variable-length subnet masks. Show the subnet address and subnet mask in the boxes below, color or shade the sub-subnets used in the box. This company will be using the class C address 192.168.16.0. Remember to start with your largest groups first.
0
127 255
128
192
191
223
LAN Address: 192.168.16.0/
LAN Address: 192.168.16.192/
LAN Address: 192.168.16.128/
WAN Address #1: 192.168.16.224/30 WAN Address #2: 192.168.16.228/
240
Color in the squares used with different shades to highlight each sub-subnet.
VLSM Addressing
Problem 3 Using the network diagram and information given create an addressing scheme which utilizes variable-length subnet masks. Show the subnet address and subnet mask in the boxes below, color or shade the sub-subnets used in the box. This company will be using the class C address 190.10.10.0. Remember to start with your largest groups first.
LAN Address:
LAN Address:
WAN Address #1:
Color in the squares used with different shades to highlight each sub-subnet. 0
127 255
128
63 64
95
112
VLSM Addressing
Problem 5 Using the network diagram and information given create an addressing scheme which utilizes variable-length subnet masks. Show the subnet address and subnet mask in the boxes below, color or shade the sub- subnets used in the box. This company will be using the class C address 192.168.10.0. Remember to start with your largest groups first.
LAN Address:
LAN Address:
WAN Address #2:
Color in the squares used with different shades to highlight each sub-subnet.
LAN Address:
LAN Address:
WAN Address #1:
VLSM Addressing
Problem 6 Using the network diagram and information given create an addressing scheme which utilizes variable-length subnet masks. Show the subnet address and subnet mask in the boxes below, color or shade the sub- subnets used in the box. This company will be using the class C address 222.10.150.0. Remember to start with your largest groups first.
LAN Address:
WAN Address #1:
Draw the necessary lines and color in the used squares with different shades to highlight each sub-subnet.
WAN Address #2:
LAN Address:
LAN Address:
LAN Address:
0
127 255
128
63 64 192
191
32
31
95
96
159
223
224
160
VLSM Addressing
Problem 8 Using the network diagram and information given create an addressing scheme which utilizes variable-length subnet masks. Show the subnet address and subnet mask in the boxes below, color or shade the sub-subnets used in the box. This company will be using the class C address 192.168.24.0. Remember to start with your largest groups first. LAN Address:
Draw the necessary lines and color in the used squares with different shades to highlight each sub-subnet.
WAN Address #1:
LAN Address:
LAN Address:
LAN Address:
0
255
VLSM Addressing
(Sample)
Problem 9
You are developing a school network with the class C address 192.168.2.0/24.
There will be three
computer labs with 30 computers each that need to be on different sub-subnets.
Forty eight classrooms with
one computer each that will comprise a single sub-subnet.
The administrative office and guidance office
contain a total of seven computers which will need to be grouped together.
Plan for four more mini labs with
six computers to each sub-subnetwork.
Divide the network using variable length subnet masks.
Complete
the information required below.
Remember to work from largest to smallest.
Subnet
(^1234567891011121314)
SubnetAddress 192.168.2.0192.168.2.64192.168.2.96192.168.2.128192.168.2.160192.168.2.176192.168.2.184192.168.2.192192.168.2.
SubnetMask (/X)^ /26/27/27/27/28/29/29/29/
First Usable
Host 192.168.2.1192.168.2.65192.168.2.97192.168.2.129192.168.2.161192.168.2.177192.168.2.185192.168.2.193192.168.2.
Last Usable
Host 192.168.2.62192.168.2.94192.168.2.126192.168.2.158192.168.2.174192.168.2.182192.168.2.190192.168.2.198192.168.2.
BroadcastAddress 192.168.2.63192.168.2.95192.168.2.127192.168.2.159192.168.2.175192.168.2.183192.168.2.191192.168.2.199192.168.2.
VLSM Addressing
Problem 11
You are setting up a medium sized network with the class C address 222.37.34.0/24.
Marketing needs
29 computers.
Research and development needs 110 computers.
Bookkeeping will use 12 computers.
The reception area will need three computers.
Management requires 60 computers.
Divide the network
using variable length subnet masks.
Complete the information required below.
Remember to work from
largest to smallest.Subnet
(^1234567891011121314)
SubnetAddress
SubnetMask (/X)
First Usable
Host
Last Usable
Host
BroadcastAddress
VLSM Addressing
Problem 12
A shipping company needs to set up its network across several locations.
The Denver office needs six
computers.
The Waco office needs 22 computers.
The Fargo office will need five computers.
The WAN
links between all three locations need to be included in the solution.
Using the IP address 192.168.10.0/
divide the network using VLSM.
Complete the information required below.
Remember to work from largest
to smallest.Subnet
(^1234567891011121314)
SubnetAddress
SubnetMask (/X)
First Usable
Host
Last Usable
Host
BroadcastAddress
VLSM Addressing
Problem 14
A local college is setting up a campus wide network. The technology wing will be on its own network address of 192.168.250.0/24.
The office wing will include 15 computers.
There are 2 labs of 20 computers
each, 2 labs of 30 computers each and one lab of 35 computers.
Complete the information required below.
Remember to work from largest to smallest.Subnet
(^1234567891011121314)
SubnetAddress
SubnetMask (/X)
First Usable
Host
Last Usable
Host
BroadcastAddress
VLSM Addressing
Problem 15
You are setting up a network for a company in four locations.
Location A has 8 computers.
Location B
has 122 computers.
Location C has 4 computers.
Location D has 55 computers.
There is a WAN connec-
tion between all four locations.
Complete the information required below using the class C address
192.168.10.0.
Remember to work from largest to smallest.
Subnet
(^1234567891011121314)
SubnetAddress
SubnetMask (/X)
First Usable
Host
Last Usable
Host
BroadcastAddress
