RESPOSTAS DA RECUPERAÇÃO 1 – MECÂNICA DOS SÓLIDOS II
1- 𝜎1𝐶 =74,633 𝑘𝑃𝑎
𝜎2𝐶 = −27,133 𝑘𝑃𝑎
𝜏𝑚á𝑥. 𝐶
𝑝𝑙𝑎𝑛𝑜
= 50,883 𝑘𝑃𝑎
𝜎𝑚é𝑑. =23,750 𝑘𝑃𝑎
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2- 𝜎1𝑃 =19,148 𝑀𝑃𝑎
𝜎2𝑃 = −64,525 𝑀𝑃𝑎
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3- a) 𝜀1=384,868 × 10−6
𝜀2=195,132 ×10−6
b) 𝛾 𝑚á𝑥.
𝑝𝑙𝑎𝑛𝑜
=189,737 × 10−6
𝜀𝑚é𝑑. = 290,000 × 10−6
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4- 𝑎′ = 402,573 𝑚𝑚
𝑏′ = 69,434 𝑚𝑚
𝑡′ = 25,021 𝑚𝑚
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5- 𝜎𝑥=194,145 𝑀𝑃𝑎