Marco Antonio Ramirez Garcia 30/03/25
𝑊𝐶𝑆 =ɤ
ɤ−1𝑅𝑇1[(𝑃2𝑠
𝑃1)𝑥−1]+ ɤ
ɤ−1𝑅𝑇3[(𝑃4𝑠
𝑃2𝑠)𝑥−1]+ ɤ
ɤ−1𝑅𝑇5[(𝑃6
𝑃4𝑠)𝑥−1]
Sabiendo que T1=T3 Y T3=T5 por lo tanto T1=T5
𝑊𝐶𝑆 =ɤ
ɤ−1𝑅𝑇1[(𝑃2𝑠
𝑃1)𝑥−1]+ ɤ
ɤ−1𝑅𝑇1[(𝑃4𝑠
𝑃2𝑠)𝑥−1]+ ɤ
ɤ−1𝑅𝑇1[(𝑃6
𝑃4𝑠)𝑥−1]
𝑊𝐶𝑆 =ɤ
ɤ−1𝑅𝑇1[(𝑃2𝑠
𝑃1)𝑥+(𝑃4𝑠
𝑃2𝑠)𝑥+(𝑃6
𝑃4𝑠)𝑥−3]
Derivamos respecto a P2s
𝑊𝐶𝑆 =ɤ
ɤ−1𝑅𝑇1[(𝑃2𝑠
𝑃1)𝑥+(𝑃4𝑠
𝑃2𝑠)𝑥+(𝑃6
𝑃4𝑠)𝑥−3]
𝑥𝑃2𝑆
𝑋−1
𝑃1𝑋−𝑃4𝑆
𝑋𝑥
𝑃2𝑆
𝑋+1 =0
Derivamos respecto a P4s
𝑊𝐶𝑆 =ɤ
ɤ−1𝑅𝑇1[(𝑃2𝑠
𝑃1)𝑥+(𝑃4𝑠
𝑃2𝑠)𝑥+(𝑃6
𝑃4𝑠)𝑥−3]
𝑥𝑃4𝑆
𝑋−1
𝑃2𝑠
𝑋−𝑃6𝑠
𝑋𝑥
𝑃4𝑠
𝑋+1 =0
Despejamos P2s de la derivada de P2s y sustituimos en la derivada de P4s para obtener P4s
𝑥𝑃2𝑆
𝑋−1
𝑃1𝑋−𝑃4𝑆
𝑋𝑥
𝑃2𝑆
𝑋+1 =0
𝑥𝑃2𝑆
𝑋−1
𝑃1𝑋=𝑃4𝑆
𝑋𝑥
𝑃2𝑆
𝑋+1
𝑃2𝑆
𝑋−1
𝑃1𝑋=𝑃4𝑆
𝑋
𝑃2𝑆
𝑋+1
𝑃2𝑆
𝑋−1(𝑃2𝑆
𝑋+1)= 𝑃4𝑆
𝑋(𝑃1
𝑋)
𝑃2𝑆
2𝑋 =𝑃4𝑆
𝑋(𝑃1
𝑋)
𝑃2𝑆 =√𝑃4𝑆𝑃1
Sustituyendo
𝑥𝑃4𝑆
𝑋−1
√𝑃4𝑆𝑃1𝑥−𝑃6𝑠
𝑋𝑥
𝑃4𝑠
𝑋+1 =0
𝑥𝑃4𝑆
𝑋−1
√𝑃4𝑆𝑃1𝑥=𝑃6𝑠
𝑋𝑥
𝑃4𝑠
𝑋+1
