Datos de tablas
≔
Fy 50
≔
Ag 17
≔
Lb 16
≔
ϕMpx 324
≔
BF 5.69
(LRFD)
≔
Kx 1
≔
Ix 475
≔
Ky 1
≔
MpxΩ 216
≔
BF 3.82
(ASD)
≔
Pd 100
≔
Lp 8.87
≔
Pl 150
≔
Kl
⋅
⋅
(
(
Kx
)
)
Lb 12
≔
E29000
≔
I475
≔
P'l 10
≔
Lr 29.8
LRFD
≔
Pu
=
+
1.2
(
(
Pd
)
)
1.6
(
(
Pl
)
)
360
≔
Mux
=
―――――
1.6
(
(
P'l
)
)
(
(
Lb
)
)
464
Donde
≔
Cmx 1
(Extremos articulados, carga transversal entre extremos)
≔
α1
≔
Pr
=
Pu 360
≔
Pe
=
―――
⋅
⋅
π2E I
(
(
Kl
)
)
2
⋅
3.688 103
≔
Bx
=
――――
Cmx
-
1
――
⋅
α Pr
Pe 1.108
≔
M'ux
=
⋅
Bx Mux 70.923
Usando la tabla 4-1
≔
ϕPn 499
=
――
Pu
ϕPn 0.721
> 0.2
Para este método se usara la tabla H1-1a
Zona 2;
≤
≤
Lp Lb Lr
≔
ϕMnx
=
⋅
Cmx
(
(
-
ϕMpx
⋅
BF
(
(
-
Lb Lp
)
)
)
)
296.763
=
+
――
Pu
ϕPn
―
8
9⎛
⎜
⎝
―――
Mux
ϕMnx⎞
⎟
⎠0.913
≤
0.913 1.0
Si resiste