F=ρ∗g∗B∗D∗(d−D
2)
F=1000 kg
m3∗9.81 m
s2∗0.075∗0.101∗
(
0.116−0.101
2
)
=4.86 N
F=1000 kg
m3∗9.81 m
s2∗0.075∗0.101∗
(
0.136−0.101
2
)
=6.35 N
h= {(m*L)} over {(ρ*B*D*(d- {D} over {2} ))
h= {(0.24 kg*0.393 m)} over {( 1000 {kg} over {{m} ^ {3}} * 0.075*0.101 *( 0.116 - {0.101} over {2} )) } = 0.19
h= {( 0.31 kg * 0.393 m )} over {( 1000 {kg} over {{m} ^ {3}} * 0.075*0.101 *(0. 136 - {0.101} over {2} )) } =0.18
M=m∗g∗L
M=
(
0.24 kg∗9.81 m
s2∗0.393 m
)
=0.92 N∗m
M=
(
0.31 kg∗9.81 m
s2∗0.393 m
)
=1.19 N∗m
EMPUJE HIDROSTATICO
DISTANCIA AL CENTRO DE PRESIONES
MOMENTO MEDIDO
MOMENTO DE TORQUE
