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Cell Biology Multiple Choice Questions and Answers, Lecture notes of Medicine

A series of multiple choice questions and answers covering various aspects of cell biology. It explores topics such as cell structure, function, and processes, providing insights into the fundamental principles of life. The questions are designed to test understanding of key concepts and encourage critical thinking about cellular mechanisms.

Typology: Lecture notes

2024/2025

Uploaded on 02/28/2025

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Question 1
2 out of 2 points
Which of the following statements complete the sentence below correctly?
After decolorization (alcohol/acetone wash) step of Gram staining, Gram negative
bacteria are visible under microscope .....................
Selected Answer:
Answe rs:
after safranine counterstaining.
after safranine counterstaining.
due to crystal violet staining.
with no further treatment.
after iodine treatment.
Response
Feedback:
Correct answer!
Gram negative bacteria are colorless after decolorization (alcohol/acetone
wash) step due to lipid solution of LPS layer and dehydration of
peptidoglycan. They cannot be visualized without further treatment under
a microscope. They are not purple stained due to crystal violet staining, as
cells are decolorized with alcohol decolorization step. Further iodine
treatment will not impart a color for visualization under a microscope. A
counterstain (safranine) is needed to visualize them.
Question 2
2 out of 2 points
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Download Cell Biology Multiple Choice Questions and Answers and more Lecture notes Medicine in PDF only on Docsity!

Question 1

2 out of 2 points

Which of the following statements complete the sentence below correctly?

After decolorization (alcohol/acetone wash) step of Gram staining, Gram negative

bacteria are visible under microscope .....................

Selected Answer:

Answers:

after safranine counterstaining.

after safranine counterstaining.

due to crystal violet staining.

with no further treatment.

after iodine treatment.

Response

Feedback:

Correct answer!

Gram negative bacteria are colorless after decolorization (alcohol/acetone

wash) step due to lipid solution of LPS layer and dehydration of

peptidoglycan. They cannot be visualized without further treatment under

a microscope. They are not purple stained due to crystal violet staining, as

cells are decolorized with alcohol decolorization step. Further iodine

treatment will not impart a color for visualization under a microscope. A

counterstain (safranine) is needed to visualize them.

Question 2

2 out of 2 points

What does a "monochromator" do in a spectrophotometer?

Selected

Answer: It breaks up the wavelengths in the light into individual wavelengths

Answers:

It is the first type of material measured using a spectrophotometer.

It breaks a material down into individual atoms.

It emits light.

It breaks up the wavelengths in the light into individual wavelengths

Response Correct response:

Feedback:

It breaks up the wavelengths in the light into individual wavelengths.

(The specific wavelength of light needed to measure the characteristic

absorption of a solution is provided by the chromator).

Incorrect answers

All other answers are incorrect.

Question 3

0 out of 2 points

In the laboratory equipped with a high-tech spectrophotometer, the enzyme catalase is

measured by its absorbance in the UV region (at 340 nm).

Which amino acids are responsible for this absorbance? (Choose as many as

required).

Selected Answers: Tyrosine (Tyr)

Asparagine (Asn)

Answers: Tryptophan (Trp)

Tyrosine (Tyr)

Proline (Pro)

Asparagine (Asn)

Phenylalanine (Phe)

Response Correct Responses:

Feedback:

Phenylalanine, Tyrosine and Tryptophan

(These amino acid have aromatic side chains allowing them to absorb at

UV).

Incorrect responses:

Proline: An imino acid

Answers:

The phase contrast and differential interference contrast microscopes are

used for the observation of living cells in cultures.

The primary magnification of a bright-field microscope is defined by the power

of the ocular lens.

Hematoxylin is an acidic dye which stains the nucleus to purple color.

Immunohistochemistry is the technique used to identify specific tissue

components by means of a specific antigen/antibody reaction tagged with a

visible label.

The lipid containing adipocytes look empty under the light microscope due to

the organic solvents used in routine histological technique.

Response Hematoxylin is a basic dye that stains the acidic DNA, RNA etc. in the

Feedback:

nucleus to purple color.

The primary magnification of a bright-field microscope is not defined by

the power of the ocular lens but is defined by the objective lens.

Question 6

1.33333 out of 2 points

Match the following features with related domains.

They can live in extreme conditions: [a]

First amino acid during protein synthesis is formylmethionine: [b]

They have linear chromosome, and also have histone proteins: [c]

They are sensitive to antibiotics: [d]

They have 70S ribosomes and produce methionine as the first amino acid during

protein synthesis: [e]

They have membrane-enclosed organelles: [f]

Selected Match the following features with related domains.

Answer:

They can live in extreme conditions: Archaea

First amino acid during protein synthesis is formylmethionine:

Archaea

They have linear chromosome, and also have histone proteins:

Eukarya

They are sensitive to antibiotics: Bacteria

They have 70S ribosomes and produce methionine as the first amino

acid during protein synthesis: Eukarya

They have membrane-enclosed organelles: Eukarya

Answers: Match the following features with related domains.

They can live in extreme conditions: Archaea

First amino acid during protein synthesis is formylmethionine:

Bacteria

They have linear chromosome, and also have histone proteins:

Eukarya

They are sensitive to antibiotics: Bacteria

They have 70S ribosomes and produce methionine as the first amino

acid during protein synthesis: Archaea

They have membrane-enclosed organelles: Eukarya

All Answer Choices

Eukarya

Archaea

Bacteria

Question 7

2 out of 2 points

In a laboratory, a scientist observes the following features under the microscope. Which

of these observations supports cell theory?

I. Skeletal muscle cells that contain more than one nucleus.

II. Mature platelets without nucleus.

III. Epithelial cells that undergo mitosis.

IV. Endocrine gland tissue samples that contain cells as their main building blocks

Selected Answer: III and IV

Answers: II only

I and III

II and IV

III and IV

Question 8

2 out of 2 points

What is the name of the lipid class presented below?

The concentration of HOCl decreases.

The concentration of HOCl remains the same.

Response Correct Response:

Feedback:

The concentration of HOCl increases (If we add

additional hypochlorite ions to this reaction, the equilibrium will shift to the

left, in order to produce more Hypochlorous acid .)

Incorrect Response:

The concentration of HOCl decreases (If we add

additional hypochlorite ions to this reaction, the equilibrium will shift to the

left, in order to produce more Hypochlorous acid .)

The concentration of HOCl remains the same (If we add

additional hypochlorite ions to this reaction, the equilibrium will shift to the

left, in order to produce more Hypochlorous acid .)

The concentration of H 3

O

increases (If we add

additional hypochlorite ions to this reaction, the equilibrium will shift to the

left, in order to produce more Hypochlorous acid. So the hydronium ions will

decrease. )

Question 10

2 out of 2 points

Regarding the properties of a non-polar molecule or group, which of the followings are

correct? (Choose as many as required).

Selected Electrons are shared equally by the atoms.

Answers:

Non-polar molecules dissolve better in non-polar solvents.

CO

is a non-polar molecule.

Answers:

There is a large electronegativity difference between two atoms in the

bond.

One atom is more likely to donate its electrons to another atom in the

bond.

Electrons are shared equally by the atoms.

Non-polar molecules dissolve better in non-polar solvents.

CO

is a non-polar molecule.

Response Correct Responses

Feedback:

Electrons are shared equally by the atoms. (In non- polar molecules, they

form covalent bonds that atoms share the electrons equally, rather than fully

gaining or losing them.)

Non-polar molecules dissolve better in non-polar solvents. (Molecular

polarity affects solubility in that polar molecules are best solvated by polar

solvent molecules and nonpolar molecules are best solvated by nonpolar

solvent molecules )

CO

is a non-polar molecule. ( CO 2

is a linear molecule and the Oxygen (O)

atoms on each end are symmetrical. Polarity results from an unequal

sharing of valence electrons. Because of this symmetry there is no region of

unequal sharing and CO 2

is a nonpolar molecule.)

Incorrect responses

There is a large electronegativity difference between two atoms in the bond.

( No electronegativity difference between two atoms leads to a pure non-

polar covalent bond. A small electronegativity difference leads to a polar

covalent bond. A large electronegativity difference leads to an ionic bond)

One atom is more likely to donate its electrons to another atom in the bond.

(Ionic bonding is the complete transfer of valence electron(s) between

atoms.)

Question 11

2 out of 2 points

The melting point of fatty acids depends upon which parameter?

Selected Answer: Degree of unsaturation

Answers: Charge on the carbon

Position of the double bond

Degree of unsaturation

Shape of the fatty acid

Response Correct answer:

Feedback:

Degree of unsaturation.

Degree of unsaturation is defined for the fatty acids by the number of

double bonds in their hydrocarbon chain. Degree of

unsaturation increases with the number of double bonds which lowers the

melting point of the fatty acids due to formation of kink structures in their

hydrocarbon chain.

Incorrect answer:

Shape of the fatty acid

Position of the double bond

Charge on the carbon

These parameters do not affect the melting point of fatty acids because

they are not related to degree of unsaturation (the number of double

bonds) in fatty acids.

Question 12

2 out of 2 points

carbon dioxide and water.

Dehydration reactions link monomers together into polymers by releasing

water.

Question 14

2 out of 2 points

Alcohol dehydrogenase (ADH) is an enzyme requiring oxidized nicotinamide adenine

dinucleotide (NAD

) for catalytic activity. In the reaction catalyzed by ADH, an alcohol is

oxidized to an aldehyde as NAD

is reduced to NADH and dissociates from the

enzyme.

What is the main function of NAD

in this reaction?

Selected Answer: Coenzyme

Answers: Heterotropic effector

Coenzyme

Prosthetic group

Apoenzyme

Cofactor

Response Correct Response:

Feedback:

Coenzyme (NAD - NADH) is coenzyme for oxydoreduction reactions.

Incorrect responses:

Apoenzyme (protein part of an enzyme)

Prosthetic group: This is a small molecule strongly bound to the enzyme;

however, NAD+ leaves the enzyme following the reaction

Cofactor: It is a metal

Heterotropic effector: It is a molecule which either activates or inhibits an

allosteric enzyme. Heterotropic effectors are not coenzymes.

Question 15

2 out of 2 points

The active site of an enzyme will bind to which of the following molecules? (Choose as

many as required)

Selected Answers: Substrate of the reaction

Competitive inhibitors

Answers: Substrate of the reaction

Allosteric inhibitors

Noncompetitive inhibitors

Competitive inhibitors

Response Correct responses:

Feedback:

Substrate (Substrate binds to the active site)

Competitive inhibitor (Having a structure similar to the substrate, it also

binds to the active site)

Incorrect responses:

Allosteric inhibitors (They bind to a site other than the active site)

Noncompetitive inhibitors (As they do not have a structure similar to the

substrate, they bind to another site on the enzyme)

Question 16

2 out of 2 points

In comparing the alpha-helix to the beta-sheet, which statement is correct only for the

beta-sheet?

Selected It is stabilized by interchain hydrogen bonds.

Answer:

Answers: It is stabilized by interchain hydrogen bonds.

Extensive hydrogen bonds between the carbonyl oxygen (C=O) and the

amide hydrogen (N-H) of the peptide bond are formed.

It is an example of secondary protein structure.

It may be found in typical globular proteins.

Response Correct answer:

Feedback:

It is stabilized by interchain hydrogen bonds. (This is associated only with

the beta-sheet).

Incorrect answers: All others (All others are associated with BOTH alpha

helix and beta sheet).

Explanation: The beta-sheet is stabilized by interchain hydrogen bonds

found between separate polypeptide chains and by intrachain hydrogen

bonds formed between regions of a single polypeptide.

The alpha helix, however, is stabilized only by intrachain hydrogen bonds.

The incorrect statements are true for both of these secondary structural

elements.

Question 17

0 out of 2 points

Lysine is an amino acid having the following acid dissociation constants (pKa):

pK1= 2.2 (Alpha carboxyl group)

(Asp is aspartate. The amino acid which contains a secondary amine

group is proline, which does not exist in this peptide. The

two cysteine residues can, under oxidizing conditions, from

a disulfide (covalent) bond. The peptide is a heptapeptide (contains 7

amino acid residues).

Question 19

2 out of 2 points

Which of the following statements concerning "hemoglobin" are correct? (Choose as

many as required)

Selected Answers: Hemoglobin is an allosteric protein.

Hemoglobin has four subunits, two alpha and two beta.

One hemoglobin molecule contains 4 hemes.

Answers: Hemoglobin is an allosteric protein.

Hemoglobin stores oxygen in tissues.

Hemoglobin has four subunits, two alpha and two beta.

The highest structure level of hemoglobin is tertiary.

One hemoglobin molecule contains 4 hemes.

Response Correct responses:

Feedback:

Hemoglobin has four subunits, two alpha and two

beta (Hemoglobin has two alpha and two beta chains, thus four

subunits).

One hemoglobin molecule contains four hemes (Each subunit of

Hemoglobin contains one heme).

Hemoglobin is allosteric (having quarternary structure,

hemoglobin is allosteric- subunits cooperate in binding oxygen).

Incorrect responses:

The highest structure level of Hemoglobin is tertiary (No, it is

quarternary).

Hemoglobin stores oxygen in tissues (No, hemoglobin carries

oxygen in the blood to liberate to the tissues).

Question 20

2 out of 2 points

A 28-year-old female presents with fluctuating fatigue, drooping of her eyelids, difficulty

swallowing and slurred speech (myastenia gravis). The patient is given a drug

(pyridostigmine) that affects the enzyme acetylcholinesterase's activity. Acetycholinest

arase-catalyzed reaction was analyzed kinetically in the presence and absence of the

drug, and the following results are obtained:

Effect on Km (as compared to No drug): Apparently increased

V max: not changed (as compared to No drug)

The drug exerts its effect by what kind of mechanism?

Selected Answer: Competitive inhibition

Answers: Non-competitive inhibition

Competitive inhibition

Irreversible inhibition

Activation of the enzyme

Response Correct response:

Feedback:

Competitive inhibition (The Km is apparently increased and the Vm

unchanged)

Incorrect responses:

Activation of the enzyme: In such a case, Km is expected to increase

(as in allosteric activation).

Noncompetitive inhibition: ( The Vmax is decreased and the Km not

changed)

Irreversible inhibition: (The enzyme is completly inactivated).

Question 21

2 out of 2 points

Which of the following statements regarding enzymes is correct?

Selected Enzymes increase the rate of a reaction.

Answer:

Answers: Enzymes catalyse only reversible reactions.

Enzymes prevent changes in substrate concentrations.

Enzymes increase the rate of a reaction.

Enzymes are permanently altered by the reactions they catalyze.

Enzymes increase the activation energy required for a chemical

reaction.

Response Correct answer:

Feedback:

Enzymes increase the rate of a chemical reaction.

Incorrect answers:

Enzymes increase the activation energy required for a chemical reaction.

(Enzymes decrease the activation energy required).

Enzymes catalyse only reversible reactions. (Enzymes can

catalyze reversible or irreversible reactions).

Enzymes are permanently altered by the reactions they catalyze (No,

enzymes do not themselves get altered and can be reused for many

reactions).

Enzymes prevent changes in substrate concentrations (No, as the

reaction proceeds, the substrate concentration is decreased).

Incorrect answers:

All others

(Oxydoreductase: One species is oxidized while another is

reduced

Isomerase: Isomerization takes place

Lyase: Breaking downand forming a double bond

Ligase: Joigning two species)

Question 24

2 out of 2 points

Dihydroxyacetone phosphate, shown below, is an intermediate compound of glycolysis.

What kind of functional groups are found in this molecule? (Choose the best choice.)

Selected Answer: Hydroxyl, carbonyl and phosphate groups

Answers: Sulfhydryl, hydroxyl and carboxyl groups

Amino, phosphate and hydroxyl groups

Carboxyl, hydroxyl and phosphate groups

Hydroxyl, carbonyl and phosphate groups

Response Correct response:

Feedback:

Hydroxyl, Carbonyl and phosphate groups ( Dihydroxyacetone phosphate

contains Hydroxyl (OH), Carbonyl (C=O) and phosphate groups (PO4))

Incorrect Response:

Carboxyl, hydroxyl and phosphate groups (Dihydroxyacetone phosphate

does not contain a carboxyl (COOH) group)

Sulfhydryl, hydroxyl and carboxyl groups (Dihydroxyacetone phosphate

does not contain a carboxyl (COOH) and a Sulfhydryl (SH) group)

Amino, phosphate and hydroxyl groups (Dihydroxyacetone phosphate

does not contain an amino (NH2) group)

Question 25

2 out of 2 points

A drug interfering with microtubule formation would cause a defect in which of the

following processes? (Choose as many as possible)

Selected Movement of sperm

Answers:

Axonal transport of secretory vesicles containing a neurotransmitter

Formation of cilia

Movement of chromosomes to the opposite poles during anaphase

Answers: Movement of sperm

Splitting of cells during cytokinesis

Axonal transport of secretory vesicles containing a neurotransmitter

Formation of cilia

Movement of chromosomes to the opposite poles during anaphase

Formation of lamellipodia and filopodia

Question 26

1.5 out of 2 points

Which of the following statements regarding the cytoskeletal elements are correct?

(Choose as many as required)

Selected

Answers: Intermediate filaments are not polar, therefore do not have motor

proteins.

The motor protein for actin filaments is myosin.

Actin filaments form through a process called treadmilling.

Answers:

Intermediate filaments are not polar, therefore do not have motor

proteins.

The motor protein for actin filaments is myosin.

The motor protein kinesin is responsible of anterograde movement.

Actin filaments form through a process called treadmilling.

Intermediate filaments form by polymerization.

Question 27

0 out of 2 points

Which of the following statement is matched incorrectly?

Selected Electroencephalography ----- records electrical activity of the brain

Selected Regression in health

Answer:

Answers:

Usage of artificial intelligence and machine learning in diagnostic tools

Transplantation of engineered organoids

Regression in health

Three-dimensional printing of drugs to overcome the drug costs

Smartphone-based diagnostic tools

Response Answer: Modern medicine and translational medicine are affording people

Feedback:

longer and healthier lives. Researchers want to take improvements in

health even further. With advances in gene editing, technology to

overcome paralysis and efforts to address high drug costs, the future of

medicine is bright. In this respect, 3D printing of drugs, transplantation of

engineered organoids, smartphone-based diagnostic tools, and usage of

artificial intelligence and machine learning in diagnostic tools are all

associated with the improvement in the future of medicine.

The answer is a) Regression in health.

Question 30

2 out of 2 points

You have constructed a protein named "importin" that cannot bind to the nuclear

localization signal (NLS).

What would you expect about the effect of this change on macromolecules that traffic

between the nucleus and the cytoplasm?

Selected

Answer: Such a change would prevent macromolecules to be imported into the

nucleus.

Answers:

Such a change would prevent macromolecules to be imported into the

nucleus.

Such a change would reduce exportation of macromolecules out of the

nucleus.

Such a change would increase exportation of macromolecules out of

the nucleus.

Such a change would induce importation of macromolecules into the

nucleus.

Response Importin plays a role in transportation of macromolecules from cytoplasm

Feedback:

into the nucleus. The constructed importin protein would not be able to

import macromolecules into the nucleus since it will not bind to NLS.

Therefore, such a change would prevent macromolecules to be imported

into the nucleus.

Question 31

2 out of 2 points

Match the following functions with appropriate type of membrane proteins.

Allows a particular molecule or ion to cross the plasma membrane freely: [a]

Selectively interacts with a specific molecule or ion to cross the plasma membrane, and

this interaction triggers conformational change: [b]

Identifies the cells by the help of glucosyl residues: [c]

Shaped for specific ligand binding that triggers downstream cellular events: [d]

Catalyzes a specific reaction: [e]

Selected Match the following functions with appropriate type of membrane

Answer:

proteins.

Allows a particular molecule or ion to cross the plasma membrane

freely: Channel protein

Selectively interacts with a specific molecule or ion to cross the plasma

membrane, and this interaction triggers conformational change:

Carrier protein

Identifies the cells by the help of glucosyl residues: Cell

recognition protein

Shaped for specific ligand binding that triggers downstream cellular

events: Receptor protein

Catalyzes a specific reaction: Enzymatic protein

Answers: Match the following functions with appropriate type of membrane

proteins.

Allows a particular molecule or ion to cross the plasma membrane

freely: Channel protein

Selectively interacts with a specific molecule or ion to cross the plasma

membrane, and this interaction triggers conformational change:

Carrier protein

Identifies the cells by the help of glucosyl residues: Cell

recognition protein

Shaped for specific ligand binding that triggers downstream cellular

events: Receptor protein

Catalyzes a specific reaction: Enzymatic protein

All Answer Choices