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PHYS 3320 HW8 spring 2025, Assignments of Physics

Transmission and waves in matter. Homework 8 for E&M Spring 2025

Typology: Assignments

2024/2025

Uploaded on 03/25/2025

greg-krohn
greg-krohn 🇺🇸

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Phys3320(HW8,(due(Thurs(night,(Mar(20(2025.(((Optional(rework(due(by(Sat(noon)(
1.
A) Starting with Maxwell’s equation in matter (in terms of D and H fields) show that, for a
linear homogeneous dielectric (D= eE, B= µH) with no free charges or currents (rfree=0, Jfree =0),
the E and B fields each obey a wave equation, with a common wave speed given by
𝑣 = 1/
𝜀𝜇
.
B) Starting from the same Maxwell equations as in part A, rewrite them in integral form, and
then briefly sketch out for us the reasoning which leads to all the boundary conditions on E and
B at a planar interface between two different linear materials (labeled 1 and 2), with
permittivities and permeabilities e1, µ1 and e2, µ2, respectively. (Again, assume no free charge or
current densities)
C) Suppose I tell you
𝐴𝑒!"# + 𝐵𝑒!$# = 𝐶𝑒!%# ,.
(with nonzero constants
𝐴, 𝐵, 𝐶, 𝑎 , 𝑏, 𝑐
) is true for
all times t. Prove that
𝑎 = 𝑏 = 𝑐
, and also that
𝐴 + 𝐵 = 𝐶
2.
In Griffiths’ section 9.3.2, (Reflection and transmission at normal incidence) he finds
reflection and transmission coefficients (R and T). But he made the assumption that µ1 = µ2 = µ0.
Drop that assumption, i.e. keep µ1 and µ2 general, and find the general formulas for R and T.
To check, explicitly confirm that R+T=1, still (as it must be)
Hint: Don’t redo work Griffiths has done for you. Use whatever you need from section 9.3.2, just
be careful not to use results where he has assumed µ1 = µ2 = µ0. I claim you can express your
final results for R and T purely as very simple functions of
b
only!
3.
In my lecture notes (and/or Griffiths 9.3.3) we worked out the case of reflection and
transmission at any angle. But we considered the case where the incident E-field is polarized in
the plane of incidence. Go through that section again, but work out the different case where the
E-field is polarized perpendicular to the plane of incidence. (You should once again assume
µ1=µ2=µ0.) Thus, start with
𝐸
3
4
5
!&
(
𝑟
4
, 𝑡
)
=. 𝐸
5
',!&𝑒! (*
+
,
∙.
,
/0#)𝑦
; and
𝑘
3
4
!& = 𝑘!& sin 𝜃!& 𝑥
;
+.𝑘!& cos 𝜃!& 𝑧
E
Specifically, what I mean by “work out” is:
A) Make a clear sketch (modeled on Griffiths fig 9.15) of the geometry and angles for this case.
Then, write out what the four boundary conditions become in this case (i.e. modify Griffiths Eq
9.102 through 9.105 appropriately for this new situation).
Finally, find the new “Fresnel Equations”, i.e. a version of Eq 9.109, but for this polarization
case. Explicitly check that your Fresnel equations reduce to proper results at normal incidence.
(8 pts for this part)
B) Replicate Griffiths Figure 9.16, (but of course for this perpendicular polarization case.)
Use Mathematica (or some program) please, don’t just “sketch it”. Assume n2/n1=2.0
Briefly, discuss what is similar, and what is different, about this case from what Griffiths (and I)
solved. Is there a “Brewster’s angle” for your situation, i.e. a non-trivial angle where reflection
becomes zero?
C) Replicate Griffiths Figure 9.17 (the one at the end of 9.3) but again, for this perpendicular
polarization case, and again assuming n2/n1=2.0 and again using a computer to plot. Show that
R+T=1 for this situation, no matter what the angle. Briefly, comment on the physics!
(HW 8 continued on back )
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Phys3320 HW 8 , due Thurs night, Mar 20 2025. (Optional rework due by Sat noon)

1. A ) Starting with Maxwell’s equation in matter (in terms of D and H fields) show that, for a

linear homogeneous dielectric ( D = e E , B = μ H ) with no free charges or currents (r free

=0, J

free

the E and B fields each obey a wave equation, with a common wave speed given by 𝑣 = 1 / √

B) Starting from the same Maxwell equations as in part A, rewrite them in integral form, and

then briefly sketch out for us the reasoning which leads to all the boundary conditions on E and

B at a planar interface between two different linear materials (labeled 1 and 2), with

permittivities and permeabilities e 1

, μ 1

and e 2

, μ 2

, respectively. (Again, assume no free charge or

current densities)

C) Suppose I tell you 𝐴𝑒

!"#

!$#

!%#

, (with nonzero constants 𝐴, 𝐵, 𝐶, 𝑎, 𝑏, 𝑐) is true for

all times t. Prove that 𝑎 = 𝑏 = 𝑐, and also that 𝐴 + 𝐵 = 𝐶

2. In Griffiths’ section 9.3.2, (Reflection and transmission at normal incidence) he finds

reflection and transmission coefficients (R and T). But he made the assumption that μ 1 = μ 2 = μ 0.

Drop that assumption, i.e. keep μ 1

and μ 2

general, and find the general formulas for R and T.

To check, explicitly confirm that R+T=1, still (as it must be)

Hint: Don’t redo work Griffiths has done for you. Use whatever you need from section 9.3.2, just

be careful not to use results where he has assumed μ 1

= μ 2

= μ

I claim you can express your

final results for R and T purely as very simple functions of b only!

3. In my lecture notes (and/or Griffiths 9.3.3) we worked out the case of reflection and

transmission at any angle. But we considered the case where the incident E-field is polarized in

the plane of incidence. Go through that section again, but work out the different case where the

E-field is polarized perpendicular to the plane of incidence. (You should once again assume

μ 1

=μ 2

=μ 0

.) Thus, start with 𝐸

!&

',!&

!(*

+⃗ ∙.⃗ /0#)

𝑦; and 𝑘

!&

!&

sin 𝜃

!&

!&

cos 𝜃

!&

Specifically, what I mean by “work out” is:

A) Make a clear sketch (modeled on Griffiths fig 9.15) of the geometry and angles for this case.

Then, write out what the four boundary conditions become in this case (i.e. modify Griffiths Eq

9.102 through 9.105 appropriately for this new situation).

Finally, find the new “Fresnel Equations”, i.e. a version of Eq 9.1 09 , but for this polarization

case. Explicitly check that your Fresnel equations reduce to proper results at normal incidence.

(8 pts for this part)

B) Replicate Griffiths Figure 9.16, (but of course for this perpendicular polarization case.)

Use Mathematica (or some program) please, don’t just “sketch it”. Assume n 2

/n 1

Briefly, discuss what is similar, and what is different, about this case from what Griffiths (and I)

solved. Is there a “Brewster’s angle” for your situation, i.e. a non-trivial angle where reflection

becomes zero?

C) Replicate Griffiths Figure 9.17 (the one at the end of 9.3) but again, for this perpendicular

polarization case, and again assuming n 2

/n 1

=2.0 and again using a computer to plot. Show that

R+T=1 for this situation, no matter what the angle. Briefly, comment on the physics!

(HW 8 continued on back )

Phys3320 HW 8 , due Thurs night, Mar 20 2025. (Optional rework due by Sat noon)

4. We have considered single boundaries, but you can also have situations with multiple layers of

dielectrics, e.g. the 3-layer system shown in the figure below.

Here, assume the index of refraction of air is n 0

, the middle layer is a dielectric (n 1

), and behind

that is a 3

rd

layer, n 2

. By matching boundary conditions for all wave vectors shown in the

drawing, I claim that you can show that the transmission coefficient for light of frequency w

entering this setup is given by

!

"

!

"

"

$

"

!

"

"

"

"

"

"

$

%&

'

where d is the thickness of the middle dielectric layer.

(The derivation of this expression is not required!)

But, let’s use this result to answer two questions:

A) If you are standing outside a glass fish tank and shine a flashlight at the fish,(use n glass

n water

=1.3), what is the maximum fraction of the light intensity that can make it into the tank?

The minimum? Does the fish see you any worse or better than you can see it? Any comments?

B ) You get a summer internship with the Nikon lens company, and you are assigned the task of

designing a dielectric coating that minimizes reflection of eyeglass lenses for visible light ( l »

500 nm) Assume air has n 0

=1, glass has n 2

=1.5. What value of n 1

would you choose, and how

thick would you make the coating? (Explain your reasoning, briefly but clearly, in words as well

as equations) What does T come out to be? Comment!

(Hint: take your time on this one – it’s not just formula plugging, think a bit!)

x

z

=

dielectric 2