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Midterm Exam with Key for Structure and Functions of Biomolecules | BIS 102, Exams of Biology

Material Type: Exam; Professor: Hilt; Class: Struc-Func Biomolecules; Subject: Biological Sciences; University: University of California - Davis; Term: Fall 2015;

Typology: Exams

2014/2015

Uploaded on 12/04/2015

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Copyright UC Regents Davis campus, 2005 - 15. All Rights Reserved. May not be re-distributed without prior written consent of course instructor.
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Copyright UC Regents Davis campus, 2005 - 15. All Rights Reserved. May not be re-distributed without prior written consent of course instructor. 1of3 BIS 102 Name _ Ken _ Fall, 2015 Las First K. Hilt First Midterm Score (100): Equations: = pH ~ pKa + log {[b]/[a]}_ (Ka) (Kn) — 1 x 10°74 Kp xs (y-x) Ka =x'/y -x) pH = (pKa, + pKa,)/2 F=(q'q@)/er AG=AH-TAS pK,’s of amino acid side chains: —_D (3.9), F (4.2), H (6.0), C (8.3), Y (10.1), K (10.5), R (12.5) pKa of amino acid a-COOH (2.1); pKa of amino acid a-NH;" (9.6) pKa of oligopeptide N-terminus (7.4); pKa of oligopeptide C-terminus (3.6) 1. (8 pts.) 400 ml of 0.20 M NaOH is mixed with 150 ml of 0.10 M H3POg. What is the final pH? Show all calculations and thoughts. The pKa ’s of HsPO, are 2.12, 7.21, and 12.32. (o-4o02Ya.20 4 aol) = 6, OF wel 2Ho (o.1S0R)(0.10r Hef) = 8-1T moe Hz PAY ZAz HePOg a. 01s mak a NL O.OF mak O47 gt + pDH = fy 2. (8 pts.) 200 ml of 0.40 M NIJ; is mixed with 300 ml of 0.20 M HCI. What is the final pH? Show all calculations and thoughts. The Kb = 1.8 x 10° M. (0-200 2)(0.40 MA Hs) = 6.080 moh Nite 5 4 é “- (4 320 £)(o.20 M Hel) = 2.0690 mit d.02 mk pHs 0,06 mal MYA | De (Ke) (Ke) = 1400" pee oz. Ka = bo = ssss ap? } =e ap + 105 oe Ve x)o> | | > 2b + log 2-335 ok. = - lew ka ; i e : 4 S.sss * io” = Q.2~b + (> ®; 477) ee bom | —s,