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Let f be the function whose graph isshown in the figure below.
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Math 53 1st Semester 2021 - 2022
Homework 2
Student Name/Number: Xavier D. Domingo
Do as indicated and work independently. Upload your neat and complete solutions to our
Google Classroom on or before September 29, 2021 (11:59 pm). Submit your output in a
pdf format or in a zip file containing your photographed or scanned solutions. Name your file as
M53BF3_HW2_LastNameFirstName.pdf or M53BF3_HW2_LastNameFirstName.zip. Example:
M53BF3_HW2_PinoRodney.pdf
Let f be the function whose graph is shown in the figure below.
(1. 1 ) Evaluate f ( โ 1) , f (0) , f (2) , and f (3).
(1.2) Evaluate also
lim
๐ฅโโ 1
๐
( ๐ฅ
) , lim
๐ฅโ 0
๐
( ๐ฅ
) , lim
๐ฅโ 2
๐
( ๐ฅ
) , lim
๐ฅโ 3
๐
( ๐ฅ
) , lim
๐ฅโโ 1
โ
๐
( ๐ฅ
) , lim
๐ฅโโ 1
๐
( ๐ฅ
) , lim
๐ฅโ 0
โ
๐
( ๐ฅ
) , lim
๐ฅโโ 1
๐
( ๐ฅ
) , lim
๐ฅโโ 2
โ
๐
( ๐ฅ
) ,
๐๐๐ lim
๐ฅโ 3
๐(๐ฅ)
(a) lim
๐ฅโโ 1
(b) lim
๐ฅโ 0
(c) lim
๐ฅโ 2
(d) lim
๐ฅโ 3
(e) lim
๐ฅโโ 1
โ
(f) lim
๐ฅโ 0
โ
(g) lim
๐ฅโ 2
โ
(h) lim
๐ฅโ 3
( 2 .) Prove using the definition of limits: lim
๐ฅโ 3
*We want to find ฮด so that when |x-3|<8, |3x- 1 - 8|< ฮต
|3x- 1 - 8|< ฮต
|3x-9|< ฮต
|3(x-3)| < ฮต
3|x-3|< ฮต
|x- 3 |<
๐
3
Delta: |x-3|<
ฮด =
๐
3
Proof:
Suppose ฮต>0 is given
Choose ฮด =
๐
3
Assume |x-3|<
๐
3
Now, |3x- 1 - 8|
=|3x- 9 |
๐ฅโ 18
โ๐ฅโ 2 โ 4
๐กโ 18
(โ๐ฅโ 2 โ 4 )(โ๐ฅโ 2 + 4 )
( ๐กโ 18
) ( โ
๐ฅโ 2 + 4 )
๐กโ 2 + 4 โ
๐กโ 2 โ 4 โ
๐กโ 2 โ 16
๐กโ 18 ( โ
๐กโ 2 + 4 )
๐กโ 2 โ 16
๐กโ 18 ( โ
๐กโ 2 + 4 )
๐กโ 18
๐กโ 18 (โ๐กโ 2 + 4 )
1
โ
๐กโ 2 + 4
1
โ 18 โ 2 + 4
1
โ
16 + 4
1
4 + 4
1
8
(d) lim
๐ฅโ
1
3
โ
[3x + 1 ] = [ 3 ( 0. 3 ) + 1 ]
๐ฅโ
1
3
๐ฅ+ 1
1 โ 3 ๐ฅ
( 1 / 3 )+ 1
1 โ 3
( 1 / 3
)
( 1 / 3 + 1 )
1 - 3 ( 1 / 3 )
4 / 3
( 1 โ 1
)( 3
)
4
0 ( 3 )
4 / 3
0
โ
PS: Sir, nag direct substitution po ako sa item na ito gamit ang fraction kasi
po nalilito po ako kapag decimal number po ginamit ko sir. Nilagyan ko din
po ng graph to prove po kasi di po ako masyadong sure sa answer ko.
๐ฅโ+โ
๐ฅ+ 1
1 โ 3 ๐ฅ
( ๐ฅ+ 1
) (
1
๐ฅ
)
( 1 โ 3 ๐ฅ
) (
1
๐ฅ
)
1 +
1
๐ฅ
1
๐ฅ
โ 3
1 + 0
0 โ 3