



Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
In these Lecture Slides, the Lecturer has tried to illustrate the following key points : Gravity, Rocks, Gravity’S Effects, Downward Acceleration, Change With Location, Experience, Gravitational Forces, Information, Gravity Surveying, Projectiles
Typology: Slides
1 / 5
This page cannot be seen from the preview
Don't miss anything!
x = 0
x
θ
2 z
m g (^) vert G
r
m g (^) vert G
Directly over the sphere (r = z) all of
the additional acceleration is vertical
and given by the relationship derived
earlier.
At some location, x, away from the sphere,
only part of the acceleration is vertical and
the vertical component is found by
trigonometry.
δ gnet
It is not convenient to calculate θ, so
we can reformulate the equation in
terms that are more convenient.
r
z
2 2 1 /^2 r = x + z
x
z r^ θ
Now plug these back into the previous
equation…
2 r
m g (^) vert G
3 r
mz g (^) vert G
δ =
Subs in cos θ…
Subs in r = …
2 2 3 /^2 x z
mz g (^) vert G
δ =
But this is based on a mass change of a
point source. Sub in the mass change of
a sphere with radius = R and density
contrast Δρ
2 2 3 /^2
3
3
x z
G R z
g (^) sphere
depends on