First Midterm Exam Solutions - Structure and Functions of Biomolecules | BIS 102, Exams of Biology

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Copyright UC Regents Davis campus, 2005 - 18. All rights reserved. May not be re-distributed without prior written consent of course instructor. lof2 BIS 102 . Name Ken Spring, 2018 Tast 7 First K. Hilt First Midterm Score (100): Equations: pH = pK, + log {[bl/al} (K,) (Ky) = 1x 10 Ky=x7/ (yx) Ky xy = x) pH=(pKg,~PpKg,V2 P= iq)ier AG=AH-TAS pK,’s of amino acid side chains: —_D (3.9), E (4.2), H (6.0), C (8.3), ¥ (10.1), K (10.5), R (12.5) pK, of amino acid «COOH (2.1); pK, of amino acid a-NHs' (9.6) pX, of oligopeptide N-tcrminus (7.4); pK, of oligopeptide C-terminus (3.6) 1. (6pts.) In class we discussed the photo below. What was this all about? Give a detailed explanation of what was being tested and what the outcome was. What was the overall conclusion? Photo rf Euglena swimnaieg in media. We ue testing the “effecta rp Zn"? deficiency (-Zuh®) and Mal? he Fiedencr Cc Mar). Outcome 2 —Znt? eobla were large, nm-motile, and had hgh concentrations of wther metals, —'Mgt® cells were mulh-Iebed ak no-pofile , dyerell emelusion + everyting in is important, inededhiing metal é. . 2. The oligopeptide AHPCILW was isolated from blood. _ (17 pts.) a) In the space below, write out the complete structure of this oligopeptide in the form that would predominate at pII 7. For one of the peptide bonds in your structure, draw a rectangle carefully around those atoms that are in a plane, due to the peptide bond. re 2 2 eee # ROK RF A) G- bye B Nem 8 min Ga Bann Bo ERE = aD \ ct, RR cH2 Cl fo cH Ho e-we HE Hoe ' t 1 me exe oon SH c cs tS Ul ! ef are, eS S 4 \ Cc a he F cre (15 pts.) b) Calculate the net charge (to the nearest 0.01) of the above oligopeptide at pH 7. Show all work. . aoe a High dane crysteing c-tep minus = “4 — dewrwaio weer on [gz glathy 2 | tapes toy & he hak oy Te b+ lon & T= FB + lem Bo I= 74 “ls ee. Le tex, “13 = leg b = = b= jor w 0.050 = b 0.BAT = % : ' ‘ “ Lae + = 0,04 “ b= O08 = 0. NTT as be = os fe Ge naag FO Net charye= a.1S * 0.07 -d.0471-1