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Cell Biology: Multiple Choice Questions and Matching Exercises, Lecture notes of Medicine

A series of multiple-choice questions and matching exercises designed to assess understanding of fundamental concepts in cell biology. It covers topics such as the structure and function of major cell organelles, the role of proteins in cell membranes, and the process of dna isolation. The exercises provide a comprehensive review of key concepts and reinforce learning through active engagement.

Typology: Lecture notes

2024/2025

Uploaded on 02/28/2025

goncasu-kobak
goncasu-kobak 🇹🇷

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Question 1
1.2 out of 1.8 points
A normal X-Ray of the left elbow joint is given below. Match the labelled structures with the correct terms.
A: [A]
B: [B]
C: [C]
D: [D]
E: [E]
F: [F]
G: [G]
H: [H]
I: [I]
J: [J]
K: [K]
L: [L]
Selected
Answer:
A normal X-Ray of the left elbow joint is given below. Match the labelled structures with the correct
terms.
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Partial preview of the text

Download Cell Biology: Multiple Choice Questions and Matching Exercises and more Lecture notes Medicine in PDF only on Docsity!

• Question 1

1.2 out of 1.8 points A normal X-Ray of the left elbow joint is given below. Match the labelled structures with the correct terms. A: [A] B: [B] C: [C] D: [D] E: [E] F: [F] G: [G] H: [H] I: [I] J: [J] K: [K] L: [L] Selected Answer: A normal X-Ray of the left elbow joint is given below. Match the labelled structures with the correct terms.

A: Lateral supracondylar ridge B: Lateral epicondyle C: Olecranon D: Trochlea E: Humeroulnar joint F: Medial supracondylar ridge G: Medial epicondyle H: Capitulum I: Humeroradial joint J: Radial head K: Neck of radius L: Radial tubercle Answers: A normal X-Ray of the left elbow joint is given below. Match the labelled structures with the correct terms.

  • Lateral epicondyle
  • Capitulum
  • Radial head
  • Lateral supracondylar ridge
  • Medial supracondylar ridge
  • Radial tubercle
  • Humeroradial joint Response Feedback: eja.png

• Question 2

1.125 out of 1.8 points Match the articulation with the correct joint type. Articulatio humero-ulnaris [A] Articulatio carpometacarpalis pollicis [B] Articulatio humeri [C] Articulationes metacarpophalangeales [D] Articulatio radio-ulnaris proximalis [E] Articulatio acromioclavicularis [F] Articulatio tibiofibularis distalis [G] Articulationes interphalangeales [H] Selected Answer: Match the articulation with the correct joint type. Articulatio humero-ulnaris Hinge Articulatio carpometacarpalis pollicis Spheroid Articulatio humeri Spheroid Articulationes metacarpophalangeales Plane Articulatio radio-ulnaris proximalis Pivot Articulatio acromioclavicularis Sellar Articulatio tibiofibularis distalis Syndesmosis Articulationes interphalangeales Hinge Answers: Match the articulation with the correct joint type. Articulatio humero-ulnaris Hinge Articulatio carpometacarpalis pollicis Sellar Articulatio humeri Spheroid Articulationes metacarpophalangeales Spheroid Articulatio radio-ulnaris proximalis Pivot Articulatio acromioclavicularis Plane Articulatio tibiofibularis distalis Syndesmosis Articulationes interphalangeales Hinge All Answer Choices

  • Spheroid
  • Sellar
  • Syndesmosis
  • Hinge
  • Pivot
  • Plane

Response Feedback: AA1 (3).png AA2 (2).png

• Question 3

1.67142 out of 1.8 points Match the following labeled structures with their correct names. A [A] B [B] C [C] D [D] E [E] F [F] G [G] H [H] I [I] J [J] K [K] L [L] M [M] N [N] Selected Answer: Match the following labeled structures with their correct names.

A Sternal end B Conoid tubercle C Corocoid process D Supraglenoid tubercle E Greater tubercle F Bicipital groove G Lesser tubercle H Deltoid tuberosity I Radial fossa J Capitulum K Trochlea L Coronoid fossa M Subscapular fossa N Glenoid cavity All Answer Choices

  • Supraspinous fossa
  • Infraraspinous fossa
  • Subscapular fossa
  • Deltoid tuberosity
  • Conoid tubercle
  • Corocoid process
  • Supraglenoid tubercle
  • Glenoid cavity
  • Greater tubercle
  • Lesser tubercle
  • Bicipital groove
  • Radial fossa
  • Capitulum
  • Trochlea
  • Coronoid fossa
  • Radial groove
  • Acromial end
  • Sternal end Response Feedback: Clavicle •A-Sternal end •B-Conoid tubercle Scapula •C-Corocoid process •D-Supraglenoid tubercle •M-Subscapular fossa •N-Glenoid cavity Humerus •E-Greater tubercle •F- Bicipital groove •G-Lesser tubercle •H-Deltoid tuberosity •I-Radial fossa •J-Capitulum •K-Trochlea •L-Coronoid fossa

• Question 4

1.2 out of 1.8 points Match the labeled bony parts in the pelvic x-ray with correct names.

A Anterior superior iliac spine B Anterior inferior iliac spine C Acetebulum D Ischial tuberosity E Symphysis pubica F Sacroiliac joint All Answer Choices

  • Sacroiliac joint
  • Anterior inferior iliac spine
  • Anterior superior iliac spine
  • Acetebulum
  • Ischial tuberosity
  • Ischial spine
  • Symphysis pubica Response Feedback: aa3.png

• Question 5

0 out of 1.7 points Which of the following bones contributes to the lateral arch of the foot? Selected Answer: Talus Answers:

Cuboid Metatarsal bone II Talus Navicular bone III Response Feedback: Arches_of_foot.jpg archesa.png

• Question 6

0 out of 1.7 points Which of the following ligaments prevents the knee joint from rotating in the anatomical position? Selected Answer: Popliteal ligament Answers: Popliteal ligament Collateral ligaments Cruciate ligaments Patellar ligament Response Feedback: When the knee joint is extended, both the collateral ligaments are tight. When it’s flexed, they become less tight. The function of the collateral ligaments is to keep the femoral and tibial condyles together, and thus to prevent the knee joint from bending from side to side. In addition to the obvious knee movements - flexion and extension - it’s also possible for the tibia to rotate a little on the femur. This rotation can happen only when the knee is flexed - when it’s extended the tightness of the collateral ligaments makes rotation impossible.

• Question 7

1.7 out of 1.7 points Which of the following order is correct from lateral to medial for distal row of the carpal bones? Selected Answer: Trapezium-Trapezoid-Capitate-Hamate Answers: Scaphoid-Lunate-Triquatral-Psiform Psiform-Triquatral-Lunate-Scaphoid Trapezium-Trapezoid-Capitate-Hamate Hamate-Capitate-Trapezoid-Trapezium Response Feedback: The proximal row of carpal bones, as seen in a lateral to medial direction on the palmar surface, include: the scaphoid bone the lunate bone the triquetral bone

Accuracy is assessed by calculating relative Standard Deviation (%RSD). Response Feedback: Correct responses:

  • Repeatability is also termed intra-assay precision.
  • Intermediate precision expresses within-laboratories variations: different days, different analysts, different equipment, etc.
  • Reproducibility expresses the precision between laboratories (collaborative studies, usually applied to standardization of methodology). Incorrect responses:
  • Repeatability expresses the precision under the same operating conditions over a long interval of time (No, repeatability expresses the precision under the same operating conditions over a shor t interval of time).
  • Accuracy is assessed by calculating relative Standard Deviation (%RSD) (No, precision is assessed by calculating relative Standard Deviation (%RSD)

• Question 10

1.8 out of 1.8 points A hypothetic mutation results in the following: Alanine is replaced by glutamic acid (In other words, Glutamic acid takes the place of alanine). Which change would be expected in the proierties of this protein? Selected Answer: Ionic interactions would increase. Answers: The number of peptide bonds would increase. Ionic interactions would increase. Hydrophobic interactions would increase. Water-solubility of the protein would decrease. A new disulfide bond would be formed. Response Feedback: Correct response: Ionic interactions would increase (Glutamic acid which incorporates into the protein is ionic). Incorrect responses: The number of peptide bonds would increase (No, the number of amino acids stays the same). Hydrophobic interactions would increase (No, glutamic acid is ionic). Water-solubility of the protein would decrease (No, it would increase because Glutamic acid is ionic). A new disulfide bond would be formed (No, cysteine is the amino acid involved in the disulfide bond).

• Question 11

1.7 out of 1.7 points

Choose the best marcomolecule group for each of the molecules explained below. This esterified molecule is stored in cells for long term energy needs and provides heat insulation [A] When we drink milk many humans can break down this dimeric molecule to its six-carbon monomers during digestion [B] This molecule acts as a biocatalyts in metabolic reaactions [C] This molecule binds to amino acids and carries them to ribosomes for translation [D] Selected Answer: Choose the best marcomolecule group for each of the molecules explained below. This esterified molecule is stored in cells for long term energy needs and provides heat insulation Lipids When we drink milk many humans can break down this dimeric molecule to its six- carbon monomers during digestion Carbohydrates This molecule acts as a biocatalyts in metabolic reaactions Proteins This molecule binds to amino acids and carries them to ribosomes for translation Nucleic Acids Answers: Choose the best marcomolecule group for each of the molecules explained below. This esterified molecule is stored in cells for long term energy needs and provides heat insulation Lipids When we drink milk many humans can break down this dimeric molecule to its six- carbon monomers during digestion Carbohydrates This molecule acts as a biocatalyts in metabolic reaactions Proteins This molecule binds to amino acids and carries them to ribosomes for translation Nucleic Acids All Answer Choices

  • Carbohydrates
  • Lipids
  • Nucleic Acids
  • Proteins

• Question 12

1.8 out of 1.8 points

Selected Answer: Choose the best number which represents the interactions listed below according to the picture of a protein above. 2 A hydrogen bond between two amino acids with polar side chains. 6 An interaction which can be distupted via introducing an organic solvent containing apolar group(s). 7 A covalent bond between side chains of two amino acids. 8 An interaction between an amino acid with an acidic side chain and another with a basic side chain.

Answers: Choose the best number which represents the interactions listed below according to the picture of a protein above. 2 A hydrogen bond between two amino acids with polar side chains. 6 An interaction which can be distupted via introducing an organic solvent containing apolar group(s). 7 A covalent bond between side chains of two amino acids. 8 An interaction between an amino acid with an acidic side chain and another with a basic side chain. All Answer Choices

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7

Response Feedback: Correct response:

  • 1 (Minus 1). the alpha carboxyl group (-COOH) of Lysine would be dissociated and have a negative charge (COO-) at a pH of 12.0 because the pH of the milieu is higher than its pKa. The pH of the milieu is higher than the pKa' s of both the alpha and the side chain amino groups and therefore the amino groups would dissociate and be in the (NH2 - no charge) form.Therefore, the net charge is - 1. Incorrect responses: All others

• Question 15

0.18 out of 1.8 points Mark all the correct statements regarding the molecule below. (Choose as many as required) Selected Answers: It is a trans poly-unsaturated fatty acid It is an omega 6 fatty acid Answers: It is a cis mono-unsaturated fatty acid It is a trans poly-unsaturated fatty acid It is an omega 4 fatty acid It is an omega 5 fatty acid It is an omega 6 fatty acid It can be a component of a triglyceride It can be a component of a phospholipid. It can be a component of a steroid hormone It can be a component of a sphingolipid It can be a component of a polysaccharide. It can be a precursor for some autocrine/paracrine signaling lipids. It is soluble in water.

• Question 16

1.35 out of 1.8 points Mark all the correct statements regarding the molecule below? (Choose as many as required)

Selected Answers: It can be polymerized via glycosidic bonds to produce glycogen. It is a component of nucleic acids It is soluble in water It contains polar regions. It is a monosaccharide Answers: It can be polymerized via glycosidic bonds to produce glycogen. It is the precursor for steroid hormones. It is a component of nucleic acids It is soluble in water It is produced when fructose is catabolized to its components It contains polar regions. It is a monosaccharide It is an amino carboxylic acid.

• Question 17

0.425 out of 1.7 points Mark alll the correct statements regarding thr molecule below. (Choose as many as required)