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CHEM 120 Exam 2: Chapters 5,6,7,
(With Answer Key) - Chamberlain
College of Nursing Examination
Study Guide 2024
CHEM 120 Exam 2: Chapters
5,6,7,8 (With Answer Key) -
Chamberlain College of Nursing
Examination Study Guide 2024
Nursing
Academy College
12 pag.
Answer Key) - Chamberlain College of Nursing Examination Study Guide 2024
CHEM 120 Exam 2: Chapters 5,6,7,8 (With Answer Key) - Chamberlain College of Nursing Examination Study Guide 2024
Exam 2 Total Points: 60
PART 1: Multiple Choice questions: Q 1-24. (2 point each)
- Chemical reactions (equations) show the following a. Reactants b. Products c. Physical state of each (gas or liquid or solid) d. All of the above
- The following is true for a mole a. It is also known as Avagadro’s number b. It contains 6.022 * 1023 molecules c. It contains mass equivalent to molecular weight d. All of the above are true
- In balancing chemical equations, the coefficients are used to a. Show number of moles b. Show volume of each in liters c. Show amount of each in grams d. Show temperature at which the substance is stable
- 2H2 + O2 2H2O means that a. 2 grams of H2 g and 1 gram of O2 gas combine to form 2 grams of water. b. 2 moles of H2 g and 1 mole of O2 gas combine to form 2 moles of water. c. 2 grams of H2 g and 1 gram of O2 gas combine to form 2 moles of water. d. 2 molecules of H2 g and 1 molecule of O2 gas combine to form 2 molecules of water.
- 2H2 + O2 2H2O. In this equation, correct method to calculate molecular mass of water is a. 2[2(mass of hydrogen) + mass of oxygen] b. 2(mass of hydrogen gas) + mass of oxygen gas c. 2(mass of hydrogen) + mass of oxygen
Answer Key) - Chamberlain College of Nursing Examination Study Guide 2024
- One mole of O2 gas contains number of molecules. a. 32 Grams b. 1 c. 6.02 * 1023 d. None of the above
- Concentration of a solution is a. Amount of solute dissolved in given amount of solvent b. Amount of solute dissolved in 1 L of solvent c. 1 g of solute dissolved in given amount of solvent d. A mass equivalent to Molecular weight of solute dissolved in given amount of solvent
- The following is a product of reaction of a nonmetal oxide with water to make acid. a. C6H12O b. H2CO c. NH4OH d. CO
- If CaO reacts with water, the following product will be made. a. Ca b. CaOH c. Ca(OH) d. H2Ca
- The following will be made when KOH reacts with HCl. a. KH b. KCl c. H2O d. B & c are true
- “The neutralization reaction is a quantitative reaction, where amount of acid needed to neutralize the base can be accurately calculated.” This statement is a. True b. False
- The pH scale represents the a. acidity of a solution b. whether the acid is strong acid or weak
Answer Key) - Chamberlain College of Nursing
Examination Study Guide 2024
Answer Key) - Chamberlain College of Nursing
Examination Study Guide 2024
Answer Key) - Chamberlain College of Nursing Examination Study Guide 2024
- Oxygen is a. a. Oxidizing agent b. Reducing agent
- Photosynthesis combines CO2 and H2O into glucose via a series of reactions. a. Oxidation b. Reduction
- Cellular Respiration generates CO2 and H2O from glucose via a series of reactions. a. Oxidation b. Reduction
- The following is true for Boyle’s law. a. At constant temperature, pressure is inversely proportional to volume. b. At constant temperature, pressure is directly proportional to volume. c. At constant pressure, temperature is inversely proportional to volume. d. At constant pressure, temperature is directly proportional to volume.
- The following is true for Charles’s law. a. At constant temperature, pressure is inversely proportional to volume. b. At constant temperature, pressure is directly proportional to volume. c. At constant pressure, temperature is inversely proportional to volume. d. At constant pressure, temperature is directly proportional to volume.
- At STP, what would be the molar mass of a gas with density of 2.1g/L? a. 10.6 g/mole b. 47 g/mole c. 0.094 g/mole d. 2.1 g/mole
PART 2: Write units and show ALL work.
- Calculate the molarity of a 250 ml solution containing 420g Aluminum hydroxide (2 points). MW of Al(OH)3 = 78 g/mole Moles of Al(OH)3 = mass/MW = 420 g/ 78 g/mole = 5.38 moles Volume = 250 mL x 1 L /1000 mL = 0.25 L M = moles /Vol in L = 5.38 moles/ 0.25L = 21.54 M
Answer Key) - Chamberlain College of Nursing Examination Study Guide 2024
- 0.5 M stock solution of NaCl was diluted to 50 mM solution in 350 ml volume. Calculate the volume needed to make this dilution. (2 points) 0.5 M x 1000 mM/1M = 500 mM
C1V1 = C2V V1 = C2V2/C1 = (50 mM x 350 mL)/500 mM = 35 mL
- (a) Complete and balance the reactions given below. (b) Answer the given question (5 points). a. 3 Ba + 2 H3PO4 Ba3(PO4)2 + 3 H Metal Acid Salt Hydrogen gas
b. Calculate the amount in gram of acid needed to produce 50 g of Salt.
MW of salt Ba3(PO4)2 = 601.2 g/mole
MW of acid (H3PO4) = 98 g/mole
Mass of given moles of given
50 g salt
Moles = mass/ MW = 50g/ 601.92 g/mole = 0.0831 moles of salt (given)
moles of given moles of unknown (USING BALANCED EQUATION)
0.0831 moles of given (salt) x 2 moles acid (unknown)/1 mole salt (given) = 0.166 moles of acid (unknown)
moles of unknown mass of unknown
moles of unknown = 0.
MW of H3PO4 = 98 g/mole
Moles = mass /MW
Mass = Moles x MW
Answer Key) - Chamberlain College of Nursing
Examination Study Guide 2024
Answer Key) - Chamberlain College of Nursing
Examination Study Guide 2024
