Solution Manual Electric Circuits ch 17, Exercises of Electronic Circuits Analysis

Download Solution Manual Electric Circuits ch 17 and more Exercises Electronic Circuits Analysis in PDF only on Docsity!

Problems 18-13 Solving simultaneously yields ay, = —4 x 1074; ay2 = —252. From J; = 0: 0 = ay1(10) — ag9(200 x 10°) From V, = 0: —0.5 x 107© = agi (5) — a22(80 x 107) Solving simultaneously yields Qa, = —5 x 1077S; gq = —0.025 Ah _ —{(1000)(20 x 10-*) — (1 x 10~*)(40)] _ == =4x 10+ (b] au hon 77) x 10 —Iyy, — —1000 _ a2 = = ag = 725 —h, _ —20 x 10-6 wey = = = 1 a1 Tai 70 5x 1077S =i St a= FT —0.025 Summary: ay, = —4x 1074; aya = —259; ag =—5 x 1077S; agp = —0.025 q In P 18.13 ==> ; = YL Vi lveeo Yar Vi lweo 2; 1, ANY Ge 102 =50Q vu WY 2200 7 -425Q v,/5 * pad av, be <— 4 =50Q2 vy #202 F-425Q a es t 2, Uu,~U_ 3H ho 3 Tq s & = 3 = = (0,1 130" 10° 20° HS y= 9p 8 3 docsity.com