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Cell Biology assignment for unit 2, Assignments of Cell Biology

Cell Biology assignment for unit 2

Typology: Assignments

2023/2024

Uploaded on 10/20/2024

loi-chua-noi
loi-chua-noi 🇻🇳

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Quest 1:
(a) At the 5-minute point: the location of these proteins indicated that protein X and
protein Y were synthesized at the free ribosome and the ER, respectively.
At the 20-30 minute point: protein X was entirely transported to the cytosol while
protein Y was being transported through the Golgi apparatus to the plasma
membrane (not entirely nor directly to the plasma membrane).
(b) Protein Z is located in the mitochondrion. It was initially synthesized at the free
ribosome and was released into the cytosol, then eventually transported to the
mitochondrion to perform its function.
(c) (I) False. At the 10-minute point, all protein Z had already been in the cytosol while a
quarter of protein X was still in the free ribosome.
(II) False. The total quantity of all four proteins remained unchanged at the 30-minute
point, so the degrading rate can not be determined.
(III) False. Similar to (II).
(IV) True. Similar to (I). It took protein X 30 minutes to be entirely transported to the
cytosol while protein Y took only 10 minutes.
Quest 2:
- Gibberellic acid treatment: produce long, thin shoots
- Ethylene treatment: produce short, fat shoots.
- Explanation: Cells elongate perpendicular to the orientation of the cellulose
microfibrils. Gibberellic acid promotes the cortical microtubule array perpendicular to
the long axis of the cell -> cells elongate parallel to its long axis. The opposite for
ethylene -> cells elongate perpendicular to its long axis.
Quest 3:
(2) Only external portions of the proteins are cleaved by the protease (it is too large to
penetrate the vesicle membrane)
(3) External and lumen portions of the proteins are cleaved by the protease (since it went
under permeabilisation treatment to penetrate the membrane)
The small fragments are cleaved protein parts while the big fragments are uncleaved protein
parts.
A. False. The bigger fragments are the uncleaved transmission portions of the protein
located in the internal of the phospholipid bilayer. They must be hydrophobic.
B. True. They are external portions that are cleaved into small fragments by protease.
C. False. Domain a should be rich in lysine since it binds to phosphate areas of the
phospholipid membrane.
D. False. Lane 2 showed two big fragments, indicating that there are two domains located
internal to the membrane -> b, c protrude into the lumen while a, d, and e protrude outside
the membrane.
Protease is too large to penetrate the membrane of vesicles. Those parts of the membrane's
proteins that are situated on the external side of the lipid bilayer are subjected to digestion
by protease, but those parts within the bilayer or lumen face of the membrane are not
affected. Under the condition of treatment with permeabilisation and protease, the
membrane no longer acts as a barrier to the penetration of the protease, so that the lumen
portions of the protein are also subjected to digestion. Under this condition (Lane 3), there
were 4 bigger fragments, indicating that domains a, b, c and d were cleaved by protease.
Under the condition of treating with protease only, protease could not enter the lumen, and
only 2 bigger fragments were, therefore, observed on the gel. This means that it was domain
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Quest 1: (a) At the 5-minute point: the location of these proteins indicated that protein X and protein Y were synthesized at the free ribosome and the ER, respectively. At the 20-30 minute point: protein X was entirely transported to the cytosol while protein Y was being transported through the Golgi apparatus to the plasma membrane (not entirely nor directly to the plasma membrane). (b) Protein Z is located in the mitochondrion. It was initially synthesized at the free ribosome and was released into the cytosol, then eventually transported to the mitochondrion to perform its function. (c) (I) False. At the 10-minute point, all protein Z had already been in the cytosol while a quarter of protein X was still in the free ribosome. (II) False. The total quantity of all four proteins remained unchanged at the 30-minute point, so the degrading rate can not be determined. (III) False. Similar to (II). (IV) True. Similar to (I). It took protein X 30 minutes to be entirely transported to the cytosol while protein Y took only 10 minutes. Quest 2:

  • Gibberellic acid treatment: produce long, thin shoots
  • Ethylene treatment: produce short, fat shoots.
  • Explanation: Cells elongate perpendicular to the orientation of the cellulose microfibrils. Gibberellic acid promotes the cortical microtubule array perpendicular to the long axis of the cell -> cells elongate parallel to its long axis. The opposite for ethylene -> cells elongate perpendicular to its long axis. Quest 3: (2) Only external portions of the proteins are cleaved by the protease (it is too large to penetrate the vesicle membrane) (3) External and lumen portions of the proteins are cleaved by the protease (since it went under permeabilisation treatment to penetrate the membrane) The small fragments are cleaved protein parts while the big fragments are uncleaved protein parts. A. False. The bigger fragments are the uncleaved transmission portions of the protein located in the internal of the phospholipid bilayer. They must be hydrophobic. B. True. They are external portions that are cleaved into small fragments by protease. C. False. Domain a should be rich in lysine since it binds to phosphate areas of the phospholipid membrane. D. False. Lane 2 showed two big fragments, indicating that there are two domains located internal to the membrane -> b, c protrude into the lumen while a, d, and e protrude outside the membrane. Protease is too large to penetrate the membrane of vesicles. Those parts of the membrane's proteins that are situated on the external side of the lipid bilayer are subjected to digestion by protease, but those parts within the bilayer or lumen face of the membrane are not affected. Under the condition of treatment with permeabilisation and protease, the membrane no longer acts as a barrier to the penetration of the protease, so that the lumen portions of the protein are also subjected to digestion. Under this condition (Lane 3), there were 4 bigger fragments, indicating that domains a, b, c and d were cleaved by protease. Under the condition of treating with protease only, protease could not enter the lumen, and only 2 bigger fragments were, therefore, observed on the gel. This means that it was domain

a, c, and e but not domains b and d were cleaved. Therefore domains a, c and e are situated on the external side of the membrane. Quest 4 a. The enzyme adds residues a monosaccharide at a time. Lane 3 showed that with only GlcNAc added, the hyaluronan synthase added one GlcNAc to the tetrasaccharide acceptor to produce a pentasaccharide chain. b. Lane 1 showed that both odd and even-number chains were produced. The dominance of odd-number chains might be caused by the faster attachment of GlcNAc compared to GlcUA. c. The enzyme adds sugar units to the nonreducing end. The chain was elongated when GlcNAc is added in lane 3, while not being elongated when GlcUA is added in lane 2 -> GlcNAc is added to GlcUA (the nonreducing end) Quest 5: a. The protease gene had a mutation. Mutation in the gene encoding some protease, inhibiting the autophagic process, might make them denatured or inactive and lose their functions. -> Autophagic bodies appeared in (2) b. Ribosome found -> the organelle was either chloroplast or mitochondria. Yeast -> no chloroplast. yeast don’t have chloroplast.