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This unit is externally assessed using an unseen paper-based examination. Pearson sets and marks the examination. The assessment must be taken under.
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68 Engineering Principles
About the test
This unit is externally assessed using an unseen paper-based examination. Pearson sets and marks the examination. The assessment must be taken under examination conditions. As the guidelines for assessment can change, you should refer to the official assessment guidance on the Pearson Qualifi cations website for the latest defi nitive guidance. Make sure you are familiar with the command words and know how to apply them within the context of the examination. The table below shows the command words for each Assessment outcome. Assessment outcome Command words AO1 calculate, describe, explain AO2 calculate, fi nd, solve AO3 fi nd, calculate, describe, draw, explain AO4 calculate, draw AO5 calculate, draw, explain Remember that all the questions are compulsory and you should attempt to answer each one.
Organise your time based on the marks available for each question. Set yourself a timetable for working through the test and then stick to it – do not spend ages on a short 1–2 mark question and then fi nd you only have a few minutes for a longer 6–7 mark question. Try answering all the simpler questions fi rst, then come back to the harder questions. This should give you more time for the harder questions.
70 Engineering Principles
Worked example
The velocity of a model rocket fired vertically upwards is given by the equation v = 2 t^2 + 5 t – 11. Find, by use of the quadratic formula, the time when the rocket reached its highest point. (2 marks)
Answer At its highest point the velocity of the rocket will have fallen to 0, so 2 t^2 + 5 t – 11 = 0 The quadratic formula takes the form
x = − b ± √
______________^ b^2 − 4 ac 2 a In this problem: a = 2, b = 5, c = −
so t =
______________________^5 2 − 4 × 2 ×^ (^ −11) 2 × 2
= 1.41 or −3.
The negative value is not valid in the context of the question, so check the answer by substituting t = 1.41 into v = 2 t^2 + 5 t – 11: v = 3.96… + 7.03… − 11 = 0 (remember to use unrounded values) The highest point will be reached after 1.41 s.
Where calculations are involved, marks are awarded for ‘knowing a method and attempting to apply it’ at each stage. It is essential, therefore, to show your working and make clear which principle or formula is being applied. Further marks are awarded for accuracy, that is, for reaching the correct numerical answer, only if the relevant method marks have already been awarded.
Worked example
An engineer is testing an inductor with an inductance of 0.5 H and a resistance of 8 Ω. It is connected to a 120 V 50 Hz a.c. supply.
Calculate the current drawn from the power supply. (3 marks)
Answer
The solution will require the calculation of I (^) rms.
The values given in the question are:
L = 0.5 H, R = 8 Ω, V rms = 120 V, f = 50 Hz
The inductive reactance is X L = 2π fL = 2π × 50 × 0.5 = 157.08 Ω.
The total impedance is given by Z = √
X L 2 + R^2 = √
So the a.c. current is I rms = ____ V rms Z
= 0.763 A or 763 mA.
Worked example
State two sources of energy loss that affect the efficiency of electrical transformers. (2 marks)
Answer
Eddy currents. Hysteresis losses.
This answer provides two accurate points and full marks would be awarded. Command words such as ‘give’, ‘state’ or ‘identify’ can be answered in single words or brief statements. There is no need to write in full sentences because the examiner is only testing your ability to recall information.