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Analyzing Smoking Trends and Academic Performance, Exercises of Mathematics

The relationship between smoking habits and academic performance among different age groups in the uk. It provides statistical analysis and visualizations to understand the trends in smoking prevalence among men and women across various age groups. The document also investigates the correlation between the number of hours students spend watching television and their test scores, revealing a negative correlation. This comprehensive analysis offers valuable insights into the complex interplay between lifestyle factors and academic outcomes, which can inform public health policies and educational strategies aimed at promoting student well-being and academic success.

Typology: Exercises

2022/2023

Uploaded on 06/09/2024

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DPS 51280 FMW01: Business Mathematics and Statistics
STATISTICS Chapter 6 and 13: In- Exercise Activity 9. Received: _____ (out of 20)
1. About what percent of x values from a normal distribution lie within one standard deviation (left and right) of the mean of that
distribution?
68% of x values lie between -1σ and +1σ of the mean
2. The heights men fellow normal distribution with mean of 160 cm and standard deviation of 11 cm. what is the approximate % of men
between 137.5cm and 182.5 cm?
z =  – 
σ = . - 
11 = -2.04545
= . - 
11 = +2.04545
About 95% of x values lie between - 2σ and +2σ of the mean
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DPS 51280 FMW01: Business Mathematics and Statistics

STATISTICS Chapter 6 and 13: In- Exercise Activity 9. Received: _____ (out of 20)

  1. About what percent of x values from a normal distribution lie within one standard deviation (left and right) of the mean of that

distribution?

68% of x values lie between -1σ and +1σ of the mean

  1. The heights men fellow normal distribution with mean of 160 cm and standard deviation of 11 cm. what is the approximate % of men

between 137.5cm and 182.5 cm?

z =

௫ – ఓ

σ

ଵଷ଻.ହ - ଵ଺଴

11

ଵ଼ଶ .ହ - ଵ଺଴

11

About 95% of x values lie between - 2σ and +2σ of the mean

  1. Suppose X ~ N(–3, 1). Between what x values does 95.45% of the data lie? The range of x values is centered at the mean of the

distribution(i.e., –3).

z =

௫ – ఓ

σ

௫ – (-ଷ)

1

௫ ା ଷ

1

-2 = x + 3 X = -2 -3 X = -

௫ – (-ଷ)

1

௫ ା ଷ

1

+2 = x + 3 X = 2 -3 X = -

About 95% of x values lie between - 5σ and -1σ of the mean

  1. The following data represents the number of hours 12 different students watched television during the weekend and the scores of each

student who took a test the following Monday.

a.) Display the scatter plot.

b.) Calculate the correlation coefficient r.

Hours, x 0 1 2 3 3 5 5 5 6 7 7 10

Test score, y 96 85 82 74 95 68 76 84 58 65 75 50

b.)

௡∑௫௬ି (∑௫)(∑௬)

ඥ௡∑௫

ି

( ∑௫

)

ඥ௡∑௬

ି

( ∑௬

)

ଵଶ(ଷ଻ଶସ)ି (ହସ)(ଽ଴଼ )

ඥଵଶ(ଷଷଶ)ିହସ

ඥଵଶ(଻଴଼ଷ଺ )ି

( ଽ଴଼

)

Negative correlation, as the number of hours spent in TV increases, the test scores tends to decrease

5. The percentage of smokers among the various age groups in UK is given in Table below:

a. Complete the table.

Age Mid-interval age Men Women

b. Plot a scatter diagram of men and women that smoke separately against age. Describe the trend and

calculate the correlation coefficient, r

MEN

0

10

20

30

40

50

60

70

0 5 10 15 20 25 30 35 40

Mid-Interval Age

Number of Smokers - Men

WOMEN

Mid-interval

age

Women xy x2 y

2

0

10

20

30

40

50

60

70

0 5 10 15 20 25 30 35

Mid-Interval Age

Number of Smokers - Women

଺(ହଵ଻ଽ.ହ)ି (ଶଷ଴)(ଵସ଺)

ඥ଺(ଵ଴ହହହ)ିଶଷ଴

ඥ଺(ଷ଻ଵସ)ି (ଵସ଺)

Negative correlation, when the age increases, the number of women that smoke tends to decrease