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Absolute Gravity Reductions: Sample Problem and Solutions, Exercises of Geodesy and Cartography

A sample problem on absolute gravity reductions, detailing the calculations required to correct gravimeter readings for various factors. It includes steps for gravitational attraction of the moon, crustal deformation, ocean loading, atmospheric reduction, and polar motion. Formulas and numerical examples, demonstrating how to determine the reduced gravimeter reading by accounting for these environmental and physical influences. This is useful for students and professionals in geophysics and geodesy. (410 characters)

Typology: Exercises

2024/2025

Available from 05/24/2025

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Sample Problem on Absolute Gravity Reductions
An absolute gravimeter located ฯ† = 23ยฐ-45โ€™-38โ€, ฮป=121ยฐ37โ€™45โ€ at the middle of an island 50m from the
shore with an elevation of 16.37 m above mean sea level. Observation took place on August 5,2024 at 10
AM local time when sea level was 3.4 meters above msl and the moon is at zenith above the gravimeter.
A mean reading of 981.3859235 Gal was recorded with atmospheric pressure of 750 mm Hg. Determine
the reduced gravimeter reading.
Solution
1. Gravitational attraction of the Moon
๐›ฟ๐‘”๐‘Ž๐‘ก๐‘ก๐‘Ÿ =๐บ๐‘š
(๐‘‘โˆ’๐‘…)2=3.55 ๐‘š๐บ๐‘Ž๐‘™ = 3550ฮผ๐บ๐‘Ž๐‘™
G=universal gravitation constant= G = 6.6743 x 10-11 m3 kg -1s-2
m=mass of the Moon= 7.342 x 1022 kg
R=mean radius of the Earth=6,371,000 m
d=371,629,000 m
2. Crustal deformation
๐›ฟ๐‘”๐‘‘๐‘’๐‘“ =๐บ๐‘€
๐‘…2โˆ’๐บ๐‘€
(๐‘…+๐›ฟโ„Ž)2=92.5 ฮผ๐บ๐‘Ž๐‘™
R=6,371,000 m
r=0.30 m
3. Ocean loading
๐›ฟ๐‘”๐‘œ=๐บ๐œŒ๐›ฅ๐›ผ(โˆš๐‘ง2
2+๐‘Ÿ12โˆ’โˆš๐‘ง1
2+๐‘Ÿ12)=41.3๐œ‡๐บ๐‘Ž๐‘™
ฯ=1,030 kg/m3
ฮ”ฮฑ =2ฯ€
Z1=12.97
Z2=16.37
r1=50 m
4. Atmospheric reduction
ฮดgP = โ€“0.36ฮผGal/millibar = โ€“3.6ฮผGal/kPa
1013.25 mbar = 760 mm Hg
ฮดgp=4.8 ฮผGal
5. Polar motion
๐›ฟ๐‘๐‘š =โˆ’1.164 ๐‘ฅ108(2๐‘Ž๐œ”2sin๐œ‘cos๐œ‘(๐‘ฅcos๐œ†โˆ’๐‘ฆsin๐œ†))= 7ฮผ๐บ๐‘Ž๐‘™
a=6,378,137 m
ฯ‰=7.292115x10-5
ฯ† = 23ยฐ-45โ€™-38โ€,
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Sample Problem on Absolute Gravity Reductions

An absolute gravimeter located ฯ† = 23ยฐ-45โ€™-38โ€, ฮป=121ยฐ37โ€™45โ€ at the middle of an island 50m from the

shore with an elevation of 16.37 m above mean sea level. Observation took place on August 5,2024 at 10

AM local time when sea level was 3 .4 meters above msl and the moon is at zenith above the gravimeter.

A mean reading of 981.3859235 Gal was recorded with atmospheric pressure of 750 mm Hg. Determine

the reduced gravimeter reading.

Solution

  1. Gravitational attraction of the Moon

๐‘Ž๐‘ก๐‘ก๐‘Ÿ

2

= 3. 55 ๐‘š๐บ๐‘Ž๐‘™ = 3550ฮผ๐บ๐‘Ž๐‘™

G=universal gravitation constant= G = 6.67 43 x 10

  • 11

m

3

kg

  • 1

s

  • 2

m=mass of the Moon= 7.342 x 10

22

kg

R=mean radius of the Earth=6,371,000 m

d=371,629,000 m

  1. Crustal deformation

๐‘‘๐‘’๐‘“

2

2

= 92. 5 ฮผ๐บ๐‘Ž๐‘™

R=6,371,000 m

r=0.30 m

  1. Ocean loading

๐‘œ

2

2

1

2

1

2

1

2

ฯ=1,030 kg/m

3

ฮ”ฮฑ =2ฯ€

Z

1

Z

2

r 1

=50 m

  1. Atmospheric reduction

ฮดg P

= โ€“ 0.36ฮผGal/millibar = โ€“ 3.6ฮผGal/kPa

1013.25 mbar = 760 mm Hg

ฮดgp=4.8 ฮผGal

  1. Polar motion

๐‘๐‘š

8

2

sin ๐œ‘ cos ๐œ‘ (๐‘ฅ cos ๐œ† โˆ’ ๐‘ฆ sin ๐œ†)) = 7 ฮผ๐บ๐‘Ž๐‘™

a=6,378,137 m

ฯ‰=7.292115x

  • 5

ฯ† = 23ยฐ-45โ€™-38โ€,

ฮป=121ยฐ37โ€™

x=0.1703โ€ 8.25 x

  • 7

y=0.4758โ€ 2.31 x 10

  • 6

reduced gravity value:

981.38592 35 Gal

๐‘Ž๐‘ก๐‘ก๐‘Ÿ

  • 0 .0000925 Gal ๐›ฟ๐‘”

๐‘‘๐‘’๐‘“

  • 0 .0000413 Gal ๐›ฟ๐‘”

๐‘œ๐‘

  • 0 .0000048 Gal ฮดgp
  • 0 .000007 Gal ๐›ฟ

๐‘๐‘š

981.38952 69 reduced reading