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8 – Stress on Thin-Walled Pressure Vessels and Pipes Description: Covers hoop and longitudinal stress analysis Applies to tanks, pipes, and cylindrical vessels Includes pressure formulas and stress safety checks
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ENGR. BON RYAN ANIBAN
other common names are circumferential stress, hoop stress, and girth stress.
other common names are circumferential stress, hoop stress, and girth stress.
the left portion of plane b-b. As shown in the figure, σL acts
of the contained fluid.
the left portion of plane b-b. As shown in the figure, σL acts
of the contained fluid.
D , and subjected to an internal pressure p. A small element of the vessel that is sufficiently removed and oriented as shown, is subjected to normal stress σS. If the spherical vessel is cut in
D , and subjected to an internal pressure p. A small element of the vessel that is sufficiently removed and oriented as shown, is subjected to normal stress σS. If the spherical vessel is cut in
Consider the wooden tank having an inner diameter D , and subjected to an internal pressure p that developed within the vessel by a contained fluid. The staves of wooden tank is bound together by steel hoops having a cross-sectional area AH and allowable stress σH. The spacing s can be determined by considering the vessel to be sectioned by planes a-a , b-b , and c-c.
Consider the wooden tank having an inner diameter D , and subjected to an internal pressure p that developed within the vessel by a contained fluid. The staves of wooden tank is bound together by steel hoops having a cross-sectional area AH and allowable stress σH. The spacing s can be determined by considering the vessel to be sectioned by planes a-a , b-b , and c-c.
𝐻
𝐻
Where: s = spacing of hoops, mm σH = allowable hoop stress, MPa AH = cross-sectional area of the hoop, mm^2 p = the internal pressure developed by the contained gas or fluid, MPa D = the inner diameter of the cylindrical vessel, mm
Determine the required thickness of the 450 mm diameter steel pipe to carry a maximum pressure of 5500 kPa if the allowable stress of steel is 124 MPa. Solution 𝜎𝑡 = 𝑝𝐷 2𝑡 124 𝑀𝑃𝑎 = ( 5. 5 MPa)( 450 mm ) 2 (𝑡) 𝑡 = 9. 980 mm 𝜎𝐿 = 𝑝𝐷 4𝑡 124 𝑀𝑃𝑎 = ( 5. 5 MPa)( 450 mm ) 4 (𝑡) 𝑡 = 4. 990 mm
A thin walled hallow sphere 3.5 m in diameter holds helium gas at 1700 kPa. Determine the minimum wall thickness of the sphere if the allowable stress is 60 MPa. Solution 𝜎𝑆 = 𝑝𝐷 4𝑡 60 𝑀𝑃𝑎 = ( 1. 7 MPa)( 3500 mm ) 4 (𝑡) 𝑡 = 24. 792 mm