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Best Actress - Mathematics - Solved Exam

Exams, Mathematics

Post: February 26th, 2013
Description
This is the Past Solved Exam of Mathematics which includes Vector, Scalar Product, Vector Product, Speed, Acceleration, Particle, Position, Magnitude, Same Direction, Scalar Field etc. Key important points are: Best Actress, Particular, Best Actor, Data, Median Age, Calculate, Comment, Common Difference, Geometric Serie, Differentiate
This is the Past Solved Exam of Mathematics which includes Vector, Scalar Product, Vector Product, Speed, Acceleration, Particle, Position, Magnitude, Same Direction, Scalar Field etc. Key important points are: Best Actress, Particular, Best Actor, Data, Median Age, Calculate, Comment, Common Difference, Geometric Serie, Differentiate
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MATH161 January 2009 Exam Solutions All questions similar to seen exercises. 1. (i) 2 9 3 4 67 5 60 where 2|9 represents 29 years of age. (ii) Sample size 10, so median is observation number 5.5. Actress median = (34 + 35)/2 = 34.5 years Actor median = (40 + 43)/2 = 41.5 years Actresses 865 5543 95 Actors 9 268 035 [4 marks] [2 marks] (iii) Actresses seem overall younger, as indicated by lower median age. Actress age distribution also slightly skewed to left, whereas actor distribution skewed to right with one outlier at age 60. [2 marks] 2. (i) P (A ∩ B ) = P (A) × P (B |A) = 0.4 × 0.5 = 0.2 (ii) P (B ) = P (A ∩ B ) + P (A ∩ B ) = 0.2 + 0.35 = 0.55 (iii) A and B not independent, because P (A) × P (B ) = 0.4 × 0.55 = 0.22 = P (A ∩ B ). (iv) Since P (C ∩ (A ∪ B )) = 0, then P (A ∪ B ∪ C ) = P (C ) + P (A ∪ B ) = P (C ) + P (A) + P (B ) − P (A ∩ B ) = 0.2 + 0.4 + 0.55 − 0.2 = 0.95 [1 mark] [2 marks] [1 marks] [3 marks] (v) A and C are not independent,..

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